$2^\sqrt2$ vs $e$, which is greater?
$(2^\sqrt2)^\sqrt2 = 4\quad $ & $\quad e^\sqrt2$ = ?
$\log(2^\sqrt2) = \sqrt2\log(2)\quad$ & $\quad \log(e) = 1$
I tried but can't induce comparable form.
Is anybody know how to prove it?
from Hot Weekly Questions - Mathematics Stack Exchange
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