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Showing that $\frac{1}{18} + \frac{1}{19} + \cdots + \frac{1}{47} < 1$ without bruce force calculation

Consider the sum $$S = \frac{1}{18} + \frac{1}{19} + \cdots + \frac{1}{47}$$. A brute-force calculation (okay, I just used Wolfram Alpha) shows that $$ S = \frac{442017301628992345493}{442720643463713815200} < 1$$

My question is whether there is some way to recognize that this sum is less than 1 without brute-force methods. For example, is there some way to pair or group the terms together so that one can say something like "These terms sum to less than 1/6, these terms sum to less than 1/6, etc., so the whole thing sums to less than 1"?

(Note: if this problem looks familiar, it may be because it is a companion to Is there an easy way to see that ${1\over5} + \frac{1}{6} + \frac{1}{7} + \frac{1}{8} + \frac{1}{9} + \frac{1}{10} + \frac{1}{11} + \frac{1}{12} > 1$?. However, in that problem, the goal was to show that a particular sum of unit fractions was greater than 1, and the answers there used the fact that $f(x) = \frac{1}{x}$ is convex to argue that certain combinations are greater than specific values. It's unclear to me whether those strategies can be adapted to show that a combination is less than a target value.)



from Hot Weekly Questions - Mathematics Stack Exchange

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