Find if $\sum\limits_{n=1}^{\infty} a^{1+\frac1{2}+\frac1{3}+\dots+\frac1{n}}$, a >0 converges or not.
I used d'Alembert's criterion and I found $\lim_{n\to \infty} \frac{x_n}{x_{n+1}}=1$
Moving to Raabe–Duhamel's test, I found $\lim_{n\to \infty} n(\frac{x_n}{x_{n+1}} -1)$ = $\lim_{n\to \infty} n(\frac{1}{\sqrt[n+1]{a}} - 1) $
What can I do from there? Or is there a better way to find if $\sum\limits_{n=1}^{\infty} a^{1+\frac1{2}+\frac1{3}+\dots+\frac1{n}}$, a >0 converges or not?
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vyavar ignut
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